STA Instruction

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Syntax: STA 16-bit
Where 16-bit is for memory location.
Byte: 3byte
Addressing Mode: Direct Addressing
Working: for execution of this instruction, microprocessor will allocate first byte for opcode, second byte for lower order address and third byte for higher order address. After execution, the content of Accumulator will be moved to the given address.
Example: STA 2000H 
where [A]= A0 H
After execution of STA 2000H
[2000H]= A0 H

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SBB

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Syntax: SBB R Where R can be any of the general purpose registers (A,B,C,D,E,H andL) Byte: 1byte Addressing Mode: Register   Addressing Working:  1.  2. A= A- R-b 3.  4. Flag Example: SBB D where  [D] = 10H , [A]= 22H and [c flag]= 1 After execution of SBB  B [A] = 11H  [D] = 10H // A= A-R-b => 22-10-1 =11H Program: write an ALP for subtraction of values present in Registers A ,B and C. Where A carries 44H and B carries 30H and C carries 10H. Store result at memory location 5000H. Label  Mnemonics  Comments Start: SUB B ;  a=a - b// 44-30= 14h            SBB  C ;  a= a - c - cy... A= 14-10-0 = 4h           STA 5000H   Stop: HLT Output: [5000H]= 04H      
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